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5c^2-44c-9=0
a = 5; b = -44; c = -9;
Δ = b2-4ac
Δ = -442-4·5·(-9)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-46}{2*5}=\frac{-2}{10} =-1/5 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+46}{2*5}=\frac{90}{10} =9 $
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